Correct answer: Nc21...c:b4[a] 2.Ne3#[A] 1...c:d4/[б]/ 2.Nb6#[Б] 1...Ne1/Ne5/Nf2/Nf4/Nc1/N:b4 2.Q:c5# 1.R1:b2?? zz 1...c:b4[a] 2.Rc2#/Ne3#[A] 1...c