Correct answer: Qe41...Be6[a]/Ba4 2.R:e6#[A] 1...Ng6+/[б]/ 2.Q:g6#[Б] 1...h5 2.Qg5# 1.Qf4? (2.Qe5#) 1...Be6[a] 2.f:e6#[C] 1...Ng6+/[б]/ 2.f:g6#[D] but 1...N