Correct answer: Ndf51...Nc4[a]/Nd1/[б]//Nd3[c] 2.Nde2#[A] 1...Nf8[d]/Ng7[d]/N:d4[d]/Nd8[d]/Nc5[e]/Nc7 2.Bc7#[Б] 1...B:c2[f] 2.Qc1#[C] 1.Q:b2? (