Correct answer: Bb41...c5[a] 2.Ne7#[A] 1...R:d7/[б]/ 2.Bb3#[Б] 1.Bd4? (2.Ne7#[A]/Bb3#[Б]) 1...c5[a] 2.R:c5#[D]/Ne7#[A] 1...R:d7/[б]/ 2.Qc5#[C]/Bb3#[Б]
