Correct answer: Nce41...N:c3[a]/Nc7/[б]//Nd6[c]/Na3[c] 2.Ncb3#[A] 1...Re2[d]/Re1[d]/Re4/Re5/Re7/Re8 2.N:f3#[Б] 1...d:c2 2.f:e3# 1...Re6+ 2.N:e6#
