Correct answer: Qc61...Kc5 2.Be7#[A] 1...c5 2.Bd2#[Б] 1.Bc1?? (2.Ba3#) but 1...b2! 1.Kb2?? zz 1...Kc5 2.Be7#[A] 1...c5 2.Bd2#[Б]/R:b3# but 1...c6! 1.