Correct answer: Nh41...Nf4[a] 2.N5g3#[A] 1...Nf6/[б]/ 2.Q:d4#[Б] 1...Nc3[c]/Nb4[c]/Nb6[c] 2.Rh4#[C] 1...B:f5 2.Q:f5# 1...e:d2 2.N:d2# 1.Nh6? (2.Q: