Correct answer: Nd51...Bd5[a]/Ra3 2.Qg4#[A] 1...Ra4 2.Re3#[Б]/Qg4#[A] 1...d5 2.Re3#[Б] 1...Ne7 2.Bd7#[C] 1.Nh:g8? (2.Re7#[D]/Bd7#[C]) 1...Bf8/<