Correct answer: Rc41...Kf4[a]/Kd6/[б]/ 2.Ng6#[A] 1...K:d4 2.Nc6# 1.Rd3? (2.Ne2#[Б]) 1...Kf4[a] 2.Ng6#[A] 1...Kd6/[б]/ 2.Nb5#[C] but 1...Bf3! 1
