Correct answer: Nd71...Kf5[a] 2.Bg6#[A] 1...K:d5/[б]/ 2.Bc6#[Б] 1...B:d5 2.Bg6#[A]/Qh7#[C] 1.Nf7? (2.Q:e6#) 1...Kf5[a] 2.Nd6#[D] 1...K:d5/[б]/ 2.
