Correct answer: Nc51...Nc3[a]/R:d2/Ra3 2.Bc5# 1...Bg2/Bg4 2.Qh8# 1...c5 2.Qd5# 1.Ne5? (2.R:d8#) 1...Nc3[a] 2.Nb3#[Б] 1...Ne3/[б]/ 2.N