Correct answer: Nc51...b:c2[a] 2.N:f3#[A]/Be5#[Б] 1...f2 2.Be5#[Б] 1.B:b3? (2.N:f3#[A]/Be5#[Б]) 1...f:e2/[б]/ 2.Qd5# 1...f6/R:d6 2.N:f3#[A] 1...Rc5 2.N
