Correct answer: Ng51...Kd4/Ng3[a]/Nh6[a]/Ne3[a]/Ne7/[б]/ 2.Qc3#[A] 1...Nd4[c] 2.Qh2#[Б] 1.Qd2? (2.N:c6#[C]) 1...Ne7/[б]/ 2.Qc3#[A] 1...Nd4[c]