Correct answer: Rd41...Ke5[a] 2.Qe7#[A] 1...d5/[б]/ 2.Rc6#[Б] 1...c2[c] 2.Ng7#[C] 1.R:b4? zz 1...Ke5[a] 2.Qe7#[A] 1...d5/[б]/ 2.Rb6#[F] 1...c2[c] 2.Ng7#[C] but 1