Correct answer: e51...B:d6[a] 2.Ng7#[A] 1...Bb4/[б]//Ba3/[б]//Bb6/[б]//Ba7[c] 2.Re5# 1.Be7? (2.Ng7#[A]/Nc7#[Б]) 1...Bb6/[б]/ 2.Ng7#[A]/Re5# but 1
