Correct answer: Qd41...Bf4[a]/Bh2/Bb2[c]/Rd4[a] 2.Rb2#[A] 1...Bd4/[б]//Rc5[d] 2.R:d3#[Б] 1.Qc7[C]? (2.Qc1#) 1...Bb2[c] 2.R:b2#[A] 1...Rc5[d] 2
