Correct answer: Na41...d3[a] 2.Q:d3# 1...Nc4/Nc8/Nd7/Na4/Na8 2.Q:c4#[A] 1.Nd3? (2.Nf6#) 1...K:e6/[б]/ 2.Nc3#[Б] 1...Ne5[c] 2.Nb4#[C] 1...
