Correct answer: Qc81...e6 2.Qg7#/Nf3#[A]/Nc6#[Б] 1...Bh7/Bd5 2.Qd5# 1...Be6 2.Nf3#[A]/Nc6#[Б] 1.Bh3? (2.Nf3#[A]) 1...Nd2[a] 2.Nc6#[Б] 1...
