Correct answer: Nb31...Bd6/Ba7 2.R:d6#[A] 1...Ng4/Nh3/Nd1/Nd3 2.B:e4# 1.N:e4? (2.Rc5#) 1...Bd6/B:e5[a] 2.R:d6#[A] 1...Q:e5/[б]/ 2.N<