Correct answer: Nc71...Ne1[a] 2.Nc4#[A] 1...Ne3/[б]/ 2.Nd3#[Б] 1...Bg4/Bf3/Be2/Bd1 2.Qh8# 1...Nh4 2.Nc4#[A]/Nd3#[Б] 1.Nf6? (2.Nc4#[A]/N