Correct answer: Nd61...e4[a] 2.Bf4#[A] 1...Be8/Bc6/[б]//Ba4/Bc8 2.Rd3#[Б] 1...g3 2.Rf3# 1.Nc5? (2.Qe4#) 1...e4[a] 2.Bf4#[A] 1...Bc6/[б]/ 2.Rd3#[Б]
