Correct answer: Ba61...Bd5[a]/Rh4/Rh3/R:h2/Rh6/Rh7/Rb5[d] 2.Nb5#[A] 1...e:d3/[б]/ 2.Na2#[Б] 1...Rc6/Rd5[c] 2.N:e4#[C] 1...Bc6/Rc4/Rb8/R<