Correct answer: Be11...Ng3[a]/Ng7[a]/Nh4[a]/Nh6[a]/N:d4[c]/N:d6[a] 2.Nd5#[A] 1...Ne7/[б]//Re6/Rd8/Rc8/Rb8/Ra8 2.Re6# 1...N:d3/Ne2/N