Correct answer: Rc2[K1...Nf5[a] 2.Bc6#[A] 1...Nd5/[б]/ 2.Bg6#[Б] 1...d3 2.Rc4# 1...Ng6/Ng8/Nc6/Nc8 2.B:g6#[Б]/Bc6#[A] 1.Rc5[C]? zz 1...Nf5[a] 2
