Correct answer: Rd81...Be1[a]/Bc3[c]/Ba5[a] 2.Nf4#[A] 1...Be3/[б]//Bg5/[б]//Bh6/[б]//Bc1/[б]//c3/[б]/ 2.Nb4#[Б] 1...f6 2.Be6# 1...c5 2.Bb7# 1...e6/e5 2.Nf6#