Correct answer: c:d51...Rd7[a]/B:b7[f] 2.f6#[A] 1...Rd6/[б]//Bd7[e] 2.N:d6#[Б] 1...Nc1/Nc5+[c]/Nd2/Nd4[d]/Na1 2.Nc5#[C] 1...Re8/Rf8/Rg8/Rh8
