Correct answer: f41...Kh4[a] 2.Nf3# 1.f3? zz 1...Kh4[a] 2.Qg4#[A] 1...f:g5/[б]/ 2.Qh7#[Б] but 1...Kh6! 1.f4! zz 1...Kh4[a] 2.Qh3#[C] 1...f:g5/[б]/ 2.Q