Correct answer: Nd61...f5 2.Bf6#[A] 1.N:g3? (2.B:f6#[A]/Qf5#[Б]) 1...Bd5[a] 2.B:f6#[A] 1...Q:g3 2.B:g3#/B:f6#[A] 1...Qf1 2.Qc3#/Qb2# 1...Q