Correct answer: N:d31...Ke4[a] 2.B:f3# 1.N:f3? (2.Q:f5#) 1...Ke4[a] 2.Nfd2#[A] 1...Ke6/[б]//Ng4[d] 2.Nd4#[Б] but 1...Be6[c]! 1.N:d7? (2.Q:f5#)
