Correct answer: e:d51...c5[a] 2.Q:d5#[A] 1...Bc4/Bd3/B:e2/[б]//Ba6 2.Qb2#[Б] 1.Qb6? (2.Qd4#) 1...c5[a] 2.Qd6#[C] 1...d:e4[d] 2.Qc5#[D] but 1...g:f5[c]! 1.
