Correct answer: Qd81...Nf3/Nf7[a]/Ng4/Ng6/Nd3/Nc4 2.c:d7#[A] 1...Nc3/Nc7/Na3/Na7 2.d:e5# 1.e:d7[A]? zz 1...Nf7[a] 2.c7#[C] 1...N:c6/[б]/ 2.Qg8
