Correct answer: Nd51...g:h4[a] 2.Bb7#[A] 1...N:c4/[б]//Nd3/Na4 2.Bf5#[Б] 1.Nf5? (2.Qe3#) 1...g:h4[a] 2.Nd6#[D] 1...N:c4/[б]/ 2.Ng3#[C] but 1...Ke5! 1