Correct answer: Be41...Be5[a] 2.Nd5#[A] 1...Ne3/[б]/ 2.Nd3#[Б] 1...Rf3/Bh3 2.Na2# 1.Qe2? (2.Nd3#[Б]/Nd5#[A]) 1...Ne3/[б]/ 2.Nd3#[Б]/Q:e3# 1.
