Correct answer: N:f71...f3 2.Nd2# 1.Q:d6? (2.Bd3#[A]/R:d4#[Б]) 1...Bg1/N:d5[a]/R:d5[c]/Rg5 2.Bd3#[A] 1...N:c4/[б]//Ra3 2.R:d4#[Б] 1...Rf6/<