Correct answer: Rfb51...Bf4[a]/Bg5[a]/Bh6[a]/Bd2[a] 2.Nb2#[A] 1.Bb4? zz 1...Bf4[a]/Bg5[a]/Bh6[a]/Bd2[a] 2.Nb2#[A] 1...Nf4/[б]//Ng1/[б]//N
