Correct answer: Kb11...N:f7[a] 2.R:f7#[A] 1...Nc4/[б]//Nc8[c]/N:b5[c]/Nb7[c] 2.R6:f4#[Б] 1...Rc8/Rb8/Bd7 2.Q:d6# 1...Ng2/Nh3/Ne2/Nd3 2.R