Correct answer: Nf41...Rg4[a]/Rg5[a]/Rg6[a]/Rg7[a]/Rg8[a] 2.B:f2#[A] 1...Rf3/[б]/ 2.Rg1#[Б] 1...Re3/R:h3 2.B:f2#[A]/Rg1#[Б] 1...f1Q/f1R 2.Q
