Correct answer: Bf61...e5+[a] 2.Nf6#[A] 1...f:g3/[б]/ 2.e4#[Б] 1...Nd3/Na2/Na6 2.B:c6#/Q:c6# 1.B:f4? (2.Nf6#[A]/e4#[Б]) 1...e5+[a] 2.Nf6#[A] but 1...N:c2! 1.g: