Correct answer: Ke41...Rb5[a] 2.Bf7#[A] 1...Rb4 2.Rc3# 1...R:b6 2.N:b6# 1.Ba4? (2.Rd4#[Б]) but 1...Rb3/[б]/! 1.c6? (2.Bf7#[A]) but 1...Rb5[a]! 1.N<