Correct answer: Nc51...Nf7[a]/Nc6/[б]//Nb7/[б]/ 2.Nc6#[A] 1...e5[c] 2.N:f5#[Б] 1...c3[d] 2.d:c3#[C] 1...f3 2.Qe3# 1.K:h6? zz 1...Nc6/[б]//Nb7/[б]/ 2.N:c6#[A] 1
