Correct answer: c41...Ka4[a] 2.Nc3# 1.c3? zz 1...Ka4[a] 2.Qb4#[A] 1...c:b5/[б]/ 2.Qa7#[Б] but 1...Ka6! 1.c4! zz 1...Ka4[a] 2.Qa3#[C] 1...c:b5/[б]/ 2.Q