Correct answer: Rb61...c:b5[a] 2.Qa3#[A] 1.Ka6? (2.Qa3#[A]) 1...R:b4/[б]/ 2.Ra5#[Б] 1...Ra1 2.Qc2# but 1...Rb3! 1.Qc3? (2.Ra5#[Б]) 1...c:b5[a] 2.Q
