Correct answer: Qc81...e6[a] 2.Qd8#[A] 1.Kb6? (2.Qd4#[C]) 1...e6[a] 2.Qd8#[A] but 1...e5/[б]/! 1.Qe8? (2.Qc6#[Б]) 1...e6[a] 2.Qd8#[A] 1...e5/[б]/ 2.Qh:e5#[D] but 1..
