Correct answer: Qe31...Rc2[a] 2.Ke3#[A]/Qe1#[Б] 1...Rb3/[б]//Ra3/[б]//Rd3/[б]//Rcg3/Rh3 2.Qe1#[Б] 1...Rc1/Re3[c] 2.Ke3#[A] 1.B:c3? (2.Ke3#[A]/<
