Correct answer: Qf51...Bd4[a]/Be3/Bf2/Bg1/Bd6/[б]//Be7/Bb4/Ba3/Bb6/Ba7 2.Qc4#[A] 1...Ng6[c]/Nh7/Nd7[e] 2.Qg8#[Б] 1...Ne6[d] 2.Q
