Correct answer: Rh11...Rh1[a] 2.Q:h1#[A]/R:h1#[Б] 1...b2 2.Kb3# 1.Qh1[A]? zz 1...R:h1[a] 2.R:h1#[Б] 1...Rc1/[б]/ 2.Q:c1#[E] 1...Rd1[c] 2.Q:d1#[F]
