Correct answer: Qg41...Rh2[a] 2.Qd5#[A] 1...Rh1/[б]/ 2.Qa2#[Б] 1.Qc8? (2.Q:h3#) 1...Rh2[a] 2.Q:b7#[C] 1...Rh1/[б]/ 2.Qc2#[D] but 1...Rf5! 1.Qe
