Correct answer: Kb61...Ke4[a] 2.Qc4#[A] 1...e4/[б]/ 2.Nf4#[Б]/Ne3# 1.Be2? (2.Qc4#[A]) 1...Ke4[a] 2.Qd3#[C] 1...e4/[б]/ 2.Nf4#[Б] but 1...Ke6! 1.Kd7??