Correct answer: Re61...R:d6[a]/Nc2/Na2/Na6 2.Re5# 1...e6 2.Rd4# 1.Ng5? (2.Rd4#) 1...Be6+/[б]/ 2.R:e6#[A] but 1...B:e4! 1.Nd4[Б]? (2.Re6#[A])