Correct answer: Rb31...Kd4[a] 2.Bc3#[A] 1...Ke5/[б]/ 2.B:f4#[Б] 1...e5 2.Qd7# 1.R:a3? (2.Q:e4#) 1...Kd4[a] 2.B:f4#[Б] 1...Ke5/[б]/ 2.Bc3#[A] 1...e5 2